(5u^2)+2u-115=0

Solution for (5u^2)+2u-115=0 equation:

(5u^2)+2u-115=0

a = 5; b = 2; c = -115;
Δ = b2-4ac
Δ = 22-4·5·(-115)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-48}{2*5}=\frac{-50}{10}
=-5
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+48}{2*5}=\frac{46}{10}
=4+3/5
$